Solve {l}{3{(2*7-x)}=2}{y=7}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 3 {(2 \cdot 7 - x)} = 2 }\\ { y = 7 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=7$$

Solution Steps

Consider the first equation. Divide both sides by 3.

$$2\times 7-x=\frac{2}{3}$$

Multiply 2 and 7 to get 14.

$$14-x=\frac{2}{3}$$

Subtract 14 from both sides.

$$-x=\frac{2}{3}-14$$

Subtract 14 from \frac{2}{3} to get -\frac{40}{3}.

$$-x=-\frac{40}{3}$$

Divide both sides by -1.

$$x=\frac{-\frac{40}{3}}{-1}$$

Express \frac{-\frac{40}{3}}{-1} as a single fraction.

$$x=\frac{-40}{3\left(-1\right)}$$

Multiply 3 and -1 to get -3.

$$x=\frac{-40}{-3}$$

Fraction \frac{-40}{-3} can be simplified to \frac{40}{3} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{40}{3}$$

The system is now solved.

$$x=\frac{40}{3} y=7 z=7$$