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Solve for x, y, z, a, b
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3x+x^{2}=x^{2}+2x+1
Consider the first equation. Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.
3x+x^{2}-x^{2}=2x+1
Subtract x^{2} from both sides.
3x=2x+1
Combine x^{2} and -x^{2} to get 0.
3x-2x=1
Subtract 2x from both sides.
x=1
Combine 3x and -2x to get x.
x=1 y=1 z=1 a=1 b=1
The system is now solved.