Solve {l}{3=2/R+5}{a=-0}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 3 = \frac{2}{R + 5} }\\ { a = -0 }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for R, a, b

$$b=0$$

Solution Steps

Consider the first equation. Variable R cannot be equal to -5 since division by zero is not defined. Multiply both sides of the equation by R+5.

$$3\left(R+5\right)=2$$

Use the distributive property to multiply 3 by R+5.

$$3R+15=2$$

Subtract 15 from both sides.

$$3R=2-15$$

Subtract 15 from 2 to get -13.

$$3R=-13$$

Divide both sides by 3.

$$R=-\frac{13}{3}$$

The system is now solved.

$$R=-\frac{13}{3} a=0 b=0$$