Solve for x, y, z
z=40
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3=-9x
Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
-9x=3
Swap sides so that all variable terms are on the left hand side.
x=\frac{3}{-9}
Divide both sides by -9.
x=-\frac{1}{3}
Reduce the fraction \frac{3}{-9} to lowest terms by extracting and canceling out 3.
x=-\frac{1}{3} y=40 z=40
The system is now solved.
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