Solve {l}{3+x=8}{y+x=0}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 3 + x = 8 }\\ { y + x = 0 }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=-5$$

Solution Steps

Consider the first equation. Subtract 3 from both sides.

$$x=8-3$$

Subtract 3 from 8 to get 5.

$$x=5$$

Consider the second equation. Insert the known values of variables into the equation.

$$y+5=0$$

Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$y=-5$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-5$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-5$$

The system is now solved.

$$x=5 y=-5 z=-5 a=-5$$