Solve {l}{3+1=y}{2{(x+1)}-y=6}{z=x}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 3 + 1 = y }\\ { 2 {(x + 1)} - y = 6 }\\ { z = x }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, x, z, a

$$a=4$$

Solution Steps

Consider the first equation. Add 3 and 1 to get 4.

$$4=y$$

Swap sides so that all variable terms are on the left hand side.

$$y=4$$

Consider the second equation. Insert the known values of variables into the equation.

$$2\left(x+1\right)-4=6$$

Use the distributive property to multiply 2 by x+1.

$$2x+2-4=6$$

Subtract 4 from 2 to get -2.

$$2x-2=6$$

Add 2 to both sides.

$$2x=6+2$$

Add 6 and 2 to get 8.

$$2x=8$$

Divide both sides by 2.

$$x=\frac{8}{2}$$

Divide 8 by 2 to get 4.

$$x=4$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=4$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=4$$

The system is now solved.

$$y=4 x=4 z=4 a=4$$