Solve {l}{25-y=320y}{z=514}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 25 - y = 320 y }\\ { z = 514 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, z, a

$$a=514$$

Solution Steps

Consider the first equation. Subtract 320y from both sides.

$$25-y-320y=0$$

Combine -y and -320y to get -321y.

$$25-321y=0$$

Subtract 25 from both sides. Anything subtracted from zero gives its negation.

$$-321y=-25$$

Divide both sides by -321.

$$y=\frac{-25}{-321}$$

Fraction \frac{-25}{-321} can be simplified to \frac{25}{321} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{25}{321}$$

The system is now solved.

$$y=\frac{25}{321} z=514 a=514$$