Solve {l}{24x+8-10x+14=12-2x+8x+34}{y=12112113}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 24 x + 8 - 10 x + 14 = 12 - 2 x + 8 x + 34 }\\ { y = 12112113 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=12112113$$

Solution Steps

Consider the first equation. Combine 24x and -10x to get 14x.

$$14x+8+14=12-2x+8x+34$$

Add 8 and 14 to get 22.

$$14x+22=12-2x+8x+34$$

Combine -2x and 8x to get 6x.

$$14x+22=12+6x+34$$

Add 12 and 34 to get 46.

$$14x+22=46+6x$$

Subtract 6x from both sides.

$$14x+22-6x=46$$

Combine 14x and -6x to get 8x.

$$8x+22=46$$

Subtract 22 from both sides.

$$8x=46-22$$

Subtract 22 from 46 to get 24.

$$8x=24$$

Divide both sides by 8.

$$x=\frac{24}{8}$$

Divide 24 by 8 to get 3.

$$x=3$$

The system is now solved.

$$x=3 y=12112113 z=12112113 a=12112113 b=12112113$$