Solve {l}{22*x=3x}{y=8x}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 22 \cdot x = 3 x }\\ { y = 8 x }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=0$$

Solution Steps

Consider the first equation. Subtract 3x from both sides.

$$22x-3x=0$$

Combine 22x and -3x to get 19x.

$$19x=0$$

Divide both sides by 19. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=8\times 0$$

Multiply 8 and 0 to get 0.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

The system is now solved.

$$x=0 y=0 z=0 a=0$$