Solve {l}{215=24x+0}{y=2x^2}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 215 = 24 x + 0 }\\ { y = 2 x ^ {2} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{46225}{288} = 160\frac{145}{288} \approx 160.503472222$$

Solution Steps

Consider the first equation. Anything plus zero gives itself.

$$215=24x$$

Swap sides so that all variable terms are on the left hand side.

$$24x=215$$

Divide both sides by 24.

$$x=\frac{215}{24}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=2\times \left(\frac{215}{24}\right)^{2}$$

Calculate \frac{215}{24} to the power of 2 and get \frac{46225}{576}.

$$y=2\times \frac{46225}{576}$$

Multiply 2 and \frac{46225}{576} to get \frac{46225}{288}.

$$y=\frac{46225}{288}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{46225}{288}$$

The system is now solved.

$$x=\frac{215}{24} y=\frac{46225}{288} z=\frac{46225}{288}$$