Solve {l}{20=y}{x=y+24}{z=x*0}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 20 = y }\\ { x = y + 24 }\\ { z = x \cdot 0 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, x, z, a

$$a=0$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$y=20$$

Consider the second equation. Insert the known values of variables into the equation.

$$x=20+24$$

Add 20 and 24 to get 44.

$$x=44$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=44\times 0$$

Multiply 44 and 0 to get 0.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

The system is now solved.

$$y=20 x=44 z=0 a=0$$