Solve {l}{20=540-x/x}{y=100}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 20 = \frac{540 - x}{x} }\\ { y = 100 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=100$$

Solution Steps

Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$20x=540-x$$

Add x to both sides.

$$20x+x=540$$

Combine 20x and x to get 21x.

$$21x=540$$

Divide both sides by 21.

$$x=\frac{540}{21}$$

Reduce the fraction \frac{540}{21} to lowest terms by extracting and canceling out 3.

$$x=\frac{180}{7}$$

The system is now solved.

$$x=\frac{180}{7} y=100 z=100$$