Solve {l}{2y=-3x+4}{y=-1}{z=5x+2}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 2 y = -3 x + 4 }\\ { y = -1 }\\ { z = 5 x + 2 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, x, z, a

$$a=12$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$2\left(-1\right)=-3x+4$$

Multiply 2 and -1 to get -2.

$$-2=-3x+4$$

Swap sides so that all variable terms are on the left hand side.

$$-3x+4=-2$$

Subtract 4 from both sides.

$$-3x=-2-4$$

Subtract 4 from -2 to get -6.

$$-3x=-6$$

Divide both sides by -3.

$$x=\frac{-6}{-3}$$

Divide -6 by -3 to get 2.

$$x=2$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=5\times 2+2$$

Multiply 5 and 2 to get 10.

$$z=10+2$$

Add 10 and 2 to get 12.

$$z=12$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=12$$

The system is now solved.

$$y=-1 x=2 z=12 a=12$$