Solve {l}{2x-y=1}{x=2}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 2 x - y = 1 }\\ { x = 2 }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=3$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$2\times 2-y=1$$

Multiply 2 and 2 to get 4.

$$4-y=1$$

Subtract 4 from both sides.

$$-y=1-4$$

Subtract 4 from 1 to get -3.

$$-y=-3$$

Divide both sides by -1.

$$y=\frac{-3}{-1}$$

Fraction \frac{-3}{-1} can be simplified to 3 by removing the negative sign from both the numerator and the denominator.

$$y=3$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=3$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=3$$

The system is now solved.

$$x=2 y=3 z=3 a=3$$