Solve {l}{2x-4=-4}{y=4-10-x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 2 x - 4 = -4 }\\ { y = 4 - 10 - x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-6$$

Solution Steps

Consider the first equation. Add 4 to both sides.

$$2x=-4+4$$

Add -4 and 4 to get 0.

$$2x=0$$

Divide both sides by 2. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=4-10-0$$

Subtract 10 from 4 to get -6.

$$y=-6-0$$

Multiply -1 and 0 to get 0.

$$y=-6+0$$

Add -6 and 0 to get -6.

$$y=-6$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-6$$

The system is now solved.

$$x=0 y=-6 z=-6$$