Solve {l}{2x+8=-0}{y=8x+5}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 2 x + 8 = -0 }\\ { y = 8 x + 5 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-27$$

Solution Steps

Consider the first equation. Subtract 8 from both sides. Anything subtracted from zero gives its negation.

$$2x=-8$$

Divide both sides by 2.

$$x=\frac{-8}{2}$$

Divide -8 by 2 to get -4.

$$x=-4$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=8\left(-4\right)+5$$

Multiply 8 and -4 to get -32.

$$y=-32+5$$

Add -32 and 5 to get -27.

$$y=-27$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-27$$

The system is now solved.

$$x=-4 y=-27 z=-27$$