Solve {l}{2x+18=20}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 2 x + 18 = 20 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=1$$

Solution Steps

Consider the first equation. Subtract 18 from both sides.

$$2x=20-18$$

Subtract 18 from 20 to get 2.

$$2x=2$$

Divide both sides by 2.

$$x=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$x=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=1$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=1$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=1$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=1$$

The system is now solved.

$$x=1 y=1 z=1 a=1 b=1 c=1$$