Solve {l}{2s+4=5{(-4-2s)}}{t=s}{text{Solvefor}utext{where}}{u=t}

$$\left. \begin{array} { l } { 2 s + 4 = 5 {(-4 - 2 s)} }\\ { t = s }\\ { \text{Solve for } u \text{ where} } \\ { u = t } \end{array} \right.$$

Solve for s, t, u

$$u=-2$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 5 by -4-2s.

$$2s+4=-20-10s$$

Add 10s to both sides.

$$2s+4+10s=-20$$

Combine 2s and 10s to get 12s.

$$12s+4=-20$$

Subtract 4 from both sides.

$$12s=-20-4$$

Subtract 4 from -20 to get -24.

$$12s=-24$$

Divide both sides by 12.

$$s=\frac{-24}{12}$$

Divide -24 by 12 to get -2.

$$s=-2$$

Consider the second equation. Insert the known values of variables into the equation.

$$t=-2$$

Consider the third equation. Insert the known values of variables into the equation.

$$u=-2$$

The system is now solved.

$$s=-2 t=-2 u=-2$$