Solve {l}{2a+1=8a}{b=5+20}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 2 a + 1 = 8 a }\\ { b = 5 + 20 }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for a, b, c, d

$$d=25$$

Solution Steps

Consider the first equation. Subtract 8a from both sides.

$$2a+1-8a=0$$

Combine 2a and -8a to get -6a.

$$-6a+1=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-6a=-1$$

Divide both sides by -6.

$$a=\frac{-1}{-6}$$

Fraction \frac{-1}{-6} can be simplified to \frac{1}{6} by removing the negative sign from both the numerator and the denominator.

$$a=\frac{1}{6}$$

Consider the second equation. Add 5 and 20 to get 25.

$$b=25$$

Consider the third equation. Insert the known values of variables into the equation.

$$c=25$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$d=25$$

The system is now solved.

$$a=\frac{1}{6} b=25 c=25 d=25$$