Solve {l}{2{(3k+5)}=-4k-30}{l=3k-2}{text{Solvefor}mtext{where}}{m=l}

$$\left. \begin{array} { l } { 2 {(3 k + 5)} = -4 k - 30 }\\ { l = 3 k - 2 }\\ { \text{Solve for } m \text{ where} } \\ { m = l } \end{array} \right.$$

Solve for k, l, m

$$m=-14$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 2 by 3k+5.

$$6k+10=-4k-30$$

Add 4k to both sides.

$$6k+10+4k=-30$$

Combine 6k and 4k to get 10k.

$$10k+10=-30$$

Subtract 10 from both sides.

$$10k=-30-10$$

Subtract 10 from -30 to get -40.

$$10k=-40$$

Divide both sides by 10.

$$k=\frac{-40}{10}$$

Divide -40 by 10 to get -4.

$$k=-4$$

Consider the second equation. Insert the known values of variables into the equation.

$$l=3\left(-4\right)-2$$

Multiply 3 and -4 to get -12.

$$l=-12-2$$

Subtract 2 from -12 to get -14.

$$l=-14$$

Consider the third equation. Insert the known values of variables into the equation.

$$m=-14$$

The system is now solved.

$$k=-4 l=-14 m=-14$$