Solve {l}{2{(3+6k)}=14}{l=k}{m=l}{text{Solvefor}ntext{where}}{n=m}

$$\left. \begin{array} { l } { 2 {(3 + 6 k)} = 14 }\\ { l = k }\\ { m = l }\\ { \text{Solve for } n \text{ where} } \\ { n = m } \end{array} \right.$$

Solve for k, l, m, n

$$n=\frac{2}{3}\approx 0.666666667$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$3+6k=\frac{14}{2}$$

Divide 14 by 2 to get 7.

$$3+6k=7$$

Subtract 3 from both sides.

$$6k=7-3$$

Subtract 3 from 7 to get 4.

$$6k=4$$

Divide both sides by 6.

$$k=\frac{4}{6}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$k=\frac{2}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$l=\frac{2}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$m=\frac{2}{3}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$n=\frac{2}{3}$$

The system is now solved.

$$k=\frac{2}{3} l=\frac{2}{3} m=\frac{2}{3} n=\frac{2}{3}$$