Solve {l}{2*{(x+4)}=30}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 2 \cdot {(x + 4)} = 30 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=11$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$x+4=\frac{30}{2}$$

Divide 30 by 2 to get 15.

$$x+4=15$$

Subtract 4 from both sides.

$$x=15-4$$

Subtract 4 from 15 to get 11.

$$x=11$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=11$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=11$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=11$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=11$$

The system is now solved.

$$x=11 y=11 z=11 a=11 b=11$$