Solve {l}{2^2=4x+1}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 2 ^ {2} = 4 x + 1 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=\frac{3}{4}=0.75$$

Solution Steps

Consider the first equation. Calculate 2 to the power of 2 and get 4.

$$4=4x+1$$

Swap sides so that all variable terms are on the left hand side.

$$4x+1=4$$

Subtract 1 from both sides.

$$4x=4-1$$

Subtract 1 from 4 to get 3.

$$4x=3$$

Divide both sides by 4.

$$x=\frac{3}{4}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{3}{4}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{3}{4}$$

The system is now solved.

$$x=\frac{3}{4} y=\frac{3}{4} z=\frac{3}{4}$$