Solve {l}{2=x+x}{y=x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 2 = x + x }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=1$$

Solution Steps

Consider the first equation. Combine x and x to get 2x.

$$2=2x$$

Swap sides so that all variable terms are on the left hand side.

$$2x=2$$

Divide both sides by 2.

$$x=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$x=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=1$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=1$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=1$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=1$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=1$$

The system is now solved.

$$x=1 y=1 z=1 a=1 b=1 c=1 d=1$$