Solve for y, z, a, b, c, d
d=1
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2+y=5y
Consider the first equation. Multiply 1 and 5 to get 5.
2+y-5y=0
Subtract 5y from both sides.
2-4y=0
Combine y and -5y to get -4y.
-4y=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
y=\frac{-2}{-4}
Divide both sides by -4.
y=\frac{1}{2}
Reduce the fraction \frac{-2}{-4} to lowest terms by extracting and canceling out -2.
y=\frac{1}{2} z=1 a=1 b=1 c=1 d=1
The system is now solved.
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