Solve {l}{2+2/x=3*3/x}{y=x}{z=-5}{a=y}{b=z}{text{Solvefor}c,dtext{where}}{c=a}{d=b}

$$\left. \begin{array} { l } { 2 + 2 / x = 3 \cdot 3 / x }\\ { y = x }\\ { z = -5 }\\ { a = y }\\ { b = z }\\ { \text{Solve for } c,d \text{ where} } \\ { c = a }\\ { d = b } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$c = \frac{7}{2} = 3\frac{1}{2} = 3.5$$

$$d=-5$$

Solution Steps

Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$x\times 2+2=3\times 3$$

Multiply 3 and 3 to get 9.

$$x\times 2+2=9$$

Subtract 2 from both sides.

$$x\times 2=9-2$$

Subtract 2 from 9 to get 7.

$$x\times 2=7$$

Divide both sides by 2.

$$x=\frac{7}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{7}{2}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=\frac{7}{2}$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=\frac{7}{2}$$

The system is now solved.

$$x=\frac{7}{2} y=\frac{7}{2} z=-5 a=\frac{7}{2} b=-5 c=\frac{7}{2} d=-5$$