Solve for b, c, d
d=3
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\frac{3}{4}b=2-2
Consider the first equation. Subtract 2 from both sides.
\frac{3}{4}b=0
Subtract 2 from 2 to get 0.
b=0
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}. Anything times zero gives zero.
b=0 c=3 d=3
The system is now solved.
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