Solve {l}{19214+3666=8+x}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 19214 + 3666 = 8 + x }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=22872$$

Solution Steps

Consider the first equation. Add 19214 and 3666 to get 22880.

$$22880=8+x$$

Swap sides so that all variable terms are on the left hand side.

$$8+x=22880$$

Subtract 8 from both sides.

$$x=22880-8$$

Subtract 8 from 22880 to get 22872.

$$x=22872$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=22872$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=22872$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=22872$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=22872$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=22872$$

The system is now solved.

$$x=22872 y=22872 z=22872 a=22872 b=22872 c=22872$$