Solve {l}{15{(x+3)}=9{(x+5)}}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 15 {(x + 3)} = 9 {(x + 5)} }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=0$$

Solution Steps

Consider the first equation. Use the distributive property to multiply 15 by x+3.

$$15x+45=9\left(x+5\right)$$

Use the distributive property to multiply 9 by x+5.

$$15x+45=9x+45$$

Subtract 9x from both sides.

$$15x+45-9x=45$$

Combine 15x and -9x to get 6x.

$$6x+45=45$$

Subtract 45 from both sides.

$$6x=45-45$$

Subtract 45 from 45 to get 0.

$$6x=0$$

Divide both sides by 6. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=0$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=0$$

The system is now solved.

$$x=0 y=0 z=0 a=0 b=0$$