Solve {l}{144a=-2}{b=-1}{c=b^2}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 144 a = -2 }\\ { b = -1 }\\ { c = b ^ {2} }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for a, b, c, d

$$d=1$$

Solution Steps

Consider the first equation. Divide both sides by 144.

$$a=\frac{-2}{144}$$

Reduce the fraction \frac{-2}{144} to lowest terms by extracting and canceling out 2.

$$a=-\frac{1}{72}$$

Consider the third equation. Insert the known values of variables into the equation.

$$c=\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$c=1$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$d=1$$

The system is now solved.

$$a=-\frac{1}{72} b=-1 c=1 d=1$$