Solve {l}{135-x=96-0}{y=4x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 135 - x = 96 - 0 }\\ { y = 4 x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=156$$

Solution Steps

Consider the first equation. Subtract 0 from 96 to get 96.

$$135-x=96$$

Subtract 135 from both sides.

$$-x=96-135$$

Subtract 135 from 96 to get -39.

$$-x=-39$$

Divide both sides by -1.

$$x=\frac{-39}{-1}$$

Fraction \frac{-39}{-1} can be simplified to 39 by removing the negative sign from both the numerator and the denominator.

$$x=39$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=4\times 39$$

Multiply 4 and 39 to get 156.

$$y=156$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=156$$

The system is now solved.

$$x=39 y=156 z=156$$