Solve {l}{12*{(7+{(15)}-8)}={(3x-18)}+{(10*{(10)})}+13}{y=2*{(7)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 12 \cdot {(7 + {(15)} - 8)} = {(3 x - 18)} + {(10 \cdot {(10)})} + 13 }\\ { y = 2 \cdot {(7)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=14$$

Solution Steps

Consider the first equation. Add 7 and 15 to get 22.

$$12\left(22-8\right)=3x-18+10\times 10+13$$

Subtract 8 from 22 to get 14.

$$12\times 14=3x-18+10\times 10+13$$

Multiply 12 and 14 to get 168.

$$168=3x-18+10\times 10+13$$

Multiply 10 and 10 to get 100.

$$168=3x-18+100+13$$

Add -18 and 100 to get 82.

$$168=3x+82+13$$

Add 82 and 13 to get 95.

$$168=3x+95$$

Swap sides so that all variable terms are on the left hand side.

$$3x+95=168$$

Subtract 95 from both sides.

$$3x=168-95$$

Subtract 95 from 168 to get 73.

$$3x=73$$

Divide both sides by 3.

$$x=\frac{73}{3}$$

Consider the second equation. Multiply 2 and 7 to get 14.

$$y=14$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=14$$

The system is now solved.

$$x=\frac{73}{3} y=14 z=14$$