Solve {l}{10x+20x=100}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 10 x + 20 x = 100 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

Solution Steps

Consider the first equation. Combine 10x and 20x to get 30x.

$$30x=100$$

Divide both sides by 30.

$$x=\frac{100}{30}$$

Reduce the fraction \frac{100}{30} to lowest terms by extracting and canceling out 10.

$$x=\frac{10}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{10}{3}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{10}{3}$$

The system is now solved.

$$x=\frac{10}{3} y=\frac{10}{3} z=\frac{10}{3}$$