Solve for x, y, z
z=295
Share
Copied to clipboard
1=13\left(x-3\right)
Consider the first equation. Variable x cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by x-3.
1=13x-39
Use the distributive property to multiply 13 by x-3.
13x-39=1
Swap sides so that all variable terms are on the left hand side.
13x=1+39
Add 39 to both sides.
13x=40
Add 1 and 39 to get 40.
x=\frac{40}{13}
Divide both sides by 13.
x=\frac{40}{13} y=295 z=295
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}