Solve {l}{0.53x+11.778=0.86}{y=0.468}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 0.53 x + 11.778 = 0.86 }\\ { y = 0.468 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=0.468$$

Solution Steps

Consider the first equation. Subtract 11.778 from both sides.

$$0.53x=0.86-11.778$$

Subtract 11.778 from 0.86 to get -10.918.

$$0.53x=-10.918$$

Divide both sides by 0.53.

$$x=\frac{-10.918}{0.53}$$

Expand \frac{-10.918}{0.53} by multiplying both numerator and the denominator by 1000.

$$x=\frac{-10918}{530}$$

Reduce the fraction \frac{-10918}{530} to lowest terms by extracting and canceling out 106.

$$x=-\frac{103}{5}$$

The system is now solved.

$$x=-\frac{103}{5} y=0.468 z=0.468 a=0.468 b=0.468 c=0.468$$