Solve {l}{0.085=I*2}{a=7}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 0.085 = I \cdot 2 }\\ { a = 7 }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for I, a, b

$$b=7$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$\frac{0.085}{2}=I$$

Expand \frac{0.085}{2} by multiplying both numerator and the denominator by 1000.

$$\frac{85}{2000}=I$$

Reduce the fraction \frac{85}{2000} to lowest terms by extracting and canceling out 5.

$$\frac{17}{400}=I$$

Swap sides so that all variable terms are on the left hand side.

$$I=\frac{17}{400}$$

The system is now solved.

$$I=\frac{17}{400} a=7 b=7$$