Solve {l}{0=x*3}{y=4*3}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 0 = x \cdot 3 }\\ { y = 4 \cdot 3 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for x, y, z, a, b

$$b=12$$

Solution Steps

Consider the first equation. Divide both sides by 3. Zero divided by any non-zero number gives zero.

$$0=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=0$$

Consider the second equation. Multiply 4 and 3 to get 12.

$$y=12$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=12$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=12$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=12$$

The system is now solved.

$$x=0 y=12 z=12 a=12 b=12$$