Solve {l}{0=4{(1-5x)}}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 0 = 4 {(1 - 5 x)} }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=\frac{1}{5}=0.2$$

Solution Steps

Consider the first equation. Divide both sides by 4. Zero divided by any non-zero number gives zero.

$$0=1-5x$$

Swap sides so that all variable terms are on the left hand side.

$$1-5x=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-5x=-1$$

Divide both sides by -5.

$$x=\frac{-1}{-5}$$

Fraction \frac{-1}{-5} can be simplified to \frac{1}{5} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\frac{1}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{1}{5}$$

The system is now solved.

$$x=\frac{1}{5} y=\frac{1}{5} z=\frac{1}{5}$$