Solve {l}{0=105+5p+7}{q=p}{text{Solvefor}rtext{where}}{r=q}

$$\left. \begin{array} { l } { 0 = 105 + 5 p + 7 }\\ { q = p }\\ { \text{Solve for } r \text{ where} } \\ { r = q } \end{array} \right.$$

Solve for p, q, r

$$r = -\frac{112}{5} = -22\frac{2}{5} = -22.4$$

Solution Steps

Consider the first equation. Add 105 and 7 to get 112.

$$0=112+5p$$

Swap sides so that all variable terms are on the left hand side.

$$112+5p=0$$

Subtract 112 from both sides. Anything subtracted from zero gives its negation.

$$5p=-112$$

Divide both sides by 5.

$$p=-\frac{112}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$q=-\frac{112}{5}$$

Consider the third equation. Insert the known values of variables into the equation.

$$r=-\frac{112}{5}$$

The system is now solved.

$$p=-\frac{112}{5} q=-\frac{112}{5} r=-\frac{112}{5}$$