Solve {l}{0=1+x-0}{y=2x^2}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 0 = 1 + x - 0 }\\ { y = 2 x ^ {2} }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solve for x, y, z, a, b, c

$$c=2$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$1+x-0=0$$

Add 0 to both sides.

$$1+x=0+0$$

Add 0 and 0 to get 0.

$$1+x=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=2\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$y=2\times 1$$

Multiply 2 and 1 to get 2.

$$y=2$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=2$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=2$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=2$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=2$$

The system is now solved.

$$x=-1 y=2 z=2 a=2 b=2 c=2$$