Solve {l}{.04x=0*4}{y={(1800)}*0*5x}{z={(1800-x)}}{a=y}{b=z}{text{Solvefor}c,dtext{where}}{c=a}{d=b}

$$\left. \begin{array} { l } { .04 x = 0 \cdot 4 }\\ { y = {(1800)} \cdot 0 \cdot 5 x }\\ { z = {(1800 - x)} }\\ { a = y }\\ { b = z }\\ { \text{Solve for } c,d \text{ where} } \\ { c = a }\\ { d = b } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$c=0$$

$$d=1800$$

Solution Steps

Consider the first equation. Multiply 0 and 4 to get 0.

$$0.04x=0$$

Divide both sides by 0.04. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=1800\times 0\times 5\times 0$$

Multiply 1800 and 0 to get 0.

$$y=0\times 5\times 0$$

Multiply 0 and 5 to get 0.

$$y=0\times 0$$

Multiply 0 and 0 to get 0.

$$y=0$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1800-0$$

Multiply -1 and 0 to get 0.

$$z=1800+0$$

Add 1800 and 0 to get 1800.

$$z=1800$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=0$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=1800$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=0$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=1800$$

The system is now solved.

$$x=0 y=0 z=1800 a=0 b=1800 c=0 d=1800$$