Solve {l}{-6*{(x+4)}=-42}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { -6 \cdot {(x + 4)} = -42 }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=3$$

Solution Steps

Consider the first equation. Divide both sides by -6.

$$x+4=\frac{-42}{-6}$$

Divide -42 by -6 to get 7.

$$x+4=7$$

Subtract 4 from both sides.

$$x=7-4$$

Subtract 4 from 7 to get 3.

$$x=3$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=3$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=3$$

The system is now solved.

$$x=3 y=3 z=3$$