Solve {l}{-4x=15-3}{y={(3x-5)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { -4 x = 15 - 3 }\\ { y = {(3 x - 5)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=-14$$

Solution Steps

Consider the first equation. Subtract 3 from 15 to get 12.

$$-4x=12$$

Divide both sides by -4.

$$x=\frac{12}{-4}$$

Divide 12 by -4 to get -3.

$$x=-3$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=3\left(-3\right)-5$$

Multiply 3 and -3 to get -9.

$$y=-9-5$$

Subtract 5 from -9 to get -14.

$$y=-14$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-14$$

The system is now solved.

$$x=-3 y=-14 z=-14$$