Solve {l}{-3{(x+3)}=28}{y=(x+3)^2}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { -3 {(x + 3)} = 28 }\\ { y = {(x + 3)} ^ {2} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z = \frac{784}{9} = 87\frac{1}{9} \approx 87.111111111$$

Solution Steps

Consider the first equation. Divide both sides by -3.

$$x+3=-\frac{28}{3}$$

Subtract 3 from both sides.

$$x=-\frac{28}{3}-3$$

Subtract 3 from -\frac{28}{3} to get -\frac{37}{3}.

$$x=-\frac{37}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=\left(-\frac{37}{3}+3\right)^{2}$$

Add -\frac{37}{3} and 3 to get -\frac{28}{3}.

$$y=\left(-\frac{28}{3}\right)^{2}$$

Calculate -\frac{28}{3} to the power of 2 and get \frac{784}{9}.

$$y=\frac{784}{9}$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=\frac{784}{9}$$

The system is now solved.

$$x=-\frac{37}{3} y=\frac{784}{9} z=\frac{784}{9}$$