Solve {l}{-28p-37=12p-5}{q=5}{text{Solvefor}rtext{where}}{r=q}

$$\left. \begin{array} { l } { -28 p - 37 = 12 p - 5 }\\ { q = 5 }\\ { \text{Solve for } r \text{ where} } \\ { r = q } \end{array} \right.$$

Solve for p, q, r

$$r=5$$

Solution Steps

Consider the first equation. Subtract 12p from both sides.

$$-28p-37-12p=-5$$

Combine -28p and -12p to get -40p.

$$-40p-37=-5$$

Add 37 to both sides.

$$-40p=-5+37$$

Add -5 and 37 to get 32.

$$-40p=32$$

Divide both sides by -40.

$$p=\frac{32}{-40}$$

Reduce the fraction \frac{32}{-40} to lowest terms by extracting and canceling out 8.

$$p=-\frac{4}{5}$$

The system is now solved.

$$p=-\frac{4}{5} q=5 r=5$$