Solve {l}{-2*{(2x-1)}+5=11-4}{y={(x+1)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { -2 \cdot {(2 x - 1)} + 5 = 11 - 4 }\\ { y = {(x + 1)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=1$$

Solution Steps

Consider the first equation. Use the distributive property to multiply -2 by 2x-1.

$$-4x+2+5=11-4$$

Add 2 and 5 to get 7.

$$-4x+7=11-4$$

Subtract 4 from 11 to get 7.

$$-4x+7=7$$

Subtract 7 from both sides.

$$-4x=7-7$$

Subtract 7 from 7 to get 0.

$$-4x=0$$

Divide both sides by -4. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=0+1$$

Add 0 and 1 to get 1.

$$y=1$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1$$

The system is now solved.

$$x=0 y=1 z=1$$