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Solve for a, b, c
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-22500+6a+2=0
Consider the first equation. Calculate 150 to the power of 2 and get 22500.
-22498+6a=0
Add -22500 and 2 to get -22498.
6a=22498
Add 22498 to both sides. Anything plus zero gives itself.
a=\frac{22498}{6}
Divide both sides by 6.
a=\frac{11249}{3}
Reduce the fraction \frac{22498}{6} to lowest terms by extracting and canceling out 2.
b=\frac{11249}{3}
Consider the second equation. Insert the known values of variables into the equation.
c=\frac{11249}{3}
Consider the third equation. Insert the known values of variables into the equation.
a=\frac{11249}{3} b=\frac{11249}{3} c=\frac{11249}{3}
The system is now solved.