Solve {l}{-1*5{(3+22t)}=12}{u=t}{v=u}{w=v}{x=w}{y=x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { -1 \cdot 5 {(3 + 22 t)} = 12 }\\ { u = t }\\ { v = u }\\ { w = v }\\ { x = w }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for t, u, v, w, x, y, z, a, b, c, d

$$d=-\frac{27}{110}\approx -0.245454545$$

Solution Steps

Consider the first equation. Multiply -1 and 5 to get -5.

$$-5\left(3+22t\right)=12$$

Use the distributive property to multiply -5 by 3+22t.

$$-15-110t=12$$

Add 15 to both sides.

$$-110t=12+15$$

Add 12 and 15 to get 27.

$$-110t=27$$

Divide both sides by -110.

$$t=-\frac{27}{110}$$

Consider the second equation. Insert the known values of variables into the equation.

$$u=-\frac{27}{110}$$

Consider the third equation. Insert the known values of variables into the equation.

$$v=-\frac{27}{110}$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$w=-\frac{27}{110}$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$x=-\frac{27}{110}$$

Consider the equation (6). Insert the known values of variables into the equation.

$$y=-\frac{27}{110}$$

Consider the equation (7). Insert the known values of variables into the equation.

$$z=-\frac{27}{110}$$

Consider the equation (8). Insert the known values of variables into the equation.

$$a=-\frac{27}{110}$$

Consider the equation (9). Insert the known values of variables into the equation.

$$b=-\frac{27}{110}$$

Consider the equation (10). Insert the known values of variables into the equation.

$$c=-\frac{27}{110}$$

Consider the equation (11). Insert the known values of variables into the equation.

$$d=-\frac{27}{110}$$

The system is now solved.

$$t=-\frac{27}{110} u=-\frac{27}{110} v=-\frac{27}{110} w=-\frac{27}{110} x=-\frac{27}{110} y=-\frac{27}{110} z=-\frac{27}{110} a=-\frac{27}{110} b=-\frac{27}{110} c=-\frac{27}{110} d=-\frac{27}{110}$$