Solve {l}{-1*5{(3+22t)}=12}{u=t}{text{Solvefor}vtext{where}}{v=u}

$$\left. \begin{array} { l } { -1 \cdot 5 {(3 + 22 t)} = 12 }\\ { u = t }\\ { \text{Solve for } v \text{ where} } \\ { v = u } \end{array} \right.$$

Solve for t, u, v

$$v=-\frac{27}{110}\approx -0.245454545$$

Solution Steps

Consider the first equation. Multiply -1 and 5 to get -5.

$$-5\left(3+22t\right)=12$$

Use the distributive property to multiply -5 by 3+22t.

$$-15-110t=12$$

Add 15 to both sides.

$$-110t=12+15$$

Add 12 and 15 to get 27.

$$-110t=27$$

Divide both sides by -110.

$$t=-\frac{27}{110}$$

Consider the second equation. Insert the known values of variables into the equation.

$$u=-\frac{27}{110}$$

Consider the third equation. Insert the known values of variables into the equation.

$$v=-\frac{27}{110}$$

The system is now solved.

$$t=-\frac{27}{110} u=-\frac{27}{110} v=-\frac{27}{110}$$