Solve {l}{-1*3{(-1*3+-9*1x)}/2*4+0*5=5*9x+1}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { -1 \cdot 3 {(-1 \cdot 3 + -9 \cdot 1 x)} / 2 \cdot 4 + 0 \cdot 5 = 5 \cdot 9 x + 1 }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=0$$

Solution Steps

Consider the first equation. Multiply both sides of the equation by 2.

$$-3\left(-3-9x\right)\times 4+0\times 5=10\times 9x+2$$

Use the distributive property to multiply -3 by -3-9x.

$$\left(9+27x\right)\times 4+0\times 5=10\times 9x+2$$

Use the distributive property to multiply 9+27x by 4.

$$36+108x+0\times 5=10\times 9x+2$$

Multiply 0 and 5 to get 0.

$$36+108x+0=10\times 9x+2$$

Add 36 and 0 to get 36.

$$36+108x=10\times 9x+2$$

Multiply 10 and 9 to get 90.

$$36+108x=90x+2$$

Subtract 90x from both sides.

$$36+108x-90x=2$$

Combine 108x and -90x to get 18x.

$$36+18x=2$$

Subtract 36 from both sides.

$$18x=2-36$$

Subtract 36 from 2 to get -34.

$$18x=-34$$

Divide both sides by 18.

$$x=\frac{-34}{18}$$

Reduce the fraction \frac{-34}{18} to lowest terms by extracting and canceling out 2.

$$x=-\frac{17}{9}$$

The system is now solved.

$$x=-\frac{17}{9} y=0 z=0$$